Difference between revisions of "TI-BASIC:1 Propzint"

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|picture=1-PROPZINT.GIF
 
|picture=1-PROPZINT.GIF
 
|summary=Computes a Z confidence interval of a proportion.
 
|summary=Computes a Z confidence interval of a proportion.
|syntax=1-PropZInt(''x'', ''n''@@[@@, ''confidence level''@@]@@)
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|syntax=1-PropZInt(''x'', ''n''<nowiki>[</nowiki>, ''confidence level''<nowiki>]</nowiki>)
 
|location=When editing a program, press:
 
|location=When editing a program, press:
 
# STAT to access the statistics menu
 
# STAT to access the statistics menu

Latest revision as of 21:39, 24 February 2016

1-PROPZINT.GIF

Command Summary

Computes a Z confidence interval of a proportion.

Command Syntax

1-PropZInt(x, n[, confidence level])

Menu Location

When editing a program, press:

  1. STAT to access the statistics menu
  2. LEFT to access the TESTS submenu
  3. ALPHA A to select 1-PropZInt(, or use arrows

(this key sequence will give you the 1-PropZInt... screen outside a program)

Calculator Compatibility

TI-83/84/+/SE

Token Size

2 bytes

The 1-PropZInt( command calculates a confidence interval for a proportion, at a specific confidence level: for example, if the confidence level is 95%, you are 95% certain that the proportion lies within the interval you get. The command assumes that the sample is large enough that the normal approximation to binomial distributions is valid: this is true if, in the sample you take, the positive and negative counts are both >5.

The 1-PropZInt( command takes 3 arguments. The first, x, is the positive count in the sample. The second, n, is the total size of the sample. (So the sample proportion is equal to x out of n). The third argument is the confidence level, which defaults to 95.

The output gives you a confidence interval of the form (a,b), meaning that the true proportion π is most likely in the range a<π<b, and the value of x/n.

Sample Problem

You want to know the proportion of students at your school that support a particular political candidate. You take a random sample of 50 students, and find that 22 of them support that candidate. 22, the positive count, and 50-22=28, the negative count, are both >5, so the assumption is satisfied.

Using 22 for x, and 50 for n, you decide to find a 95% confidence interval. The syntax for that is:

:1-PropZInt(22,50,95
which can also be
:1-PropZInt(22,50,.95

The output if you run the above code will look approximately like this:

1-PropZInt
 (.30241,.57759)
 p=.44
 n=50

This tells you that between about 30.2% and about 57.8% of the students at your school are in support of the political candidate.

Optimization

If the confidence level is 95%, you can omit the final 95, since that is the default value:


:1-PropZInt(22,50,95
can be
:1-PropZInt(22,50


Error Conditions

  • ERR:DOMAIN is thrown if the sample proportion is not between 0 and 1, any argument is negative, or the confidence level is 100 or more.

Related Commands