Difference between revisions of "TI-BASIC:Quadratic Formula"
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|summary=Solves for the complex roots of a quadratic equation. | |summary=Solves for the complex roots of a quadratic equation. | ||
|input=''A, B, C'' - the constants in Ax^^2^^+Bx+C=0 | |input=''A, B, C'' - the constants in Ax^^2^^+Bx+C=0 | ||
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|compatibility=TI-83/84/+/SE | |compatibility=TI-83/84/+/SE | ||
|author=thornahawk | |author=thornahawk | ||
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|url=http://www.unitedti.org/index.php?showtopic=7392&view=findpost&p=116156 United TI | |url=http://www.unitedti.org/index.php?showtopic=7392&view=findpost&p=116156 United TI | ||
|download=[file quadraticformula.zip] | |download=[file quadraticformula.zip] |
Revision as of 22:12, 24 February 2016
Routine Summary
Solves for the complex roots of a quadratic equation.
Inputs
A, B, C - the constants in Ax^^2^^+Bx+C=0
Outputs
Ans - a 2-element list of the two roots (or the one repeated root)
Variables Used
A, B, C
Calculator Compatibility
TI-83/84/+/SE Author
thornahawkURL: United TI Download
-2C/(B+{-1,1}√(B²+4ACi²
For optimization purposes, an alternate form of the quadratic formula is used (see below for the formulas). The {-1,1} list is used to replace the ± symbol -- lists can be used just as well as numbers in expressions, making the result a list as well. By using i² in the expression in place of subtraction, the routine avoids having to activate A+bi mode to allow complex roots.
The output is a complex list in Ans of the two roots. If there is only one root, it will be returned twice. If both roots are real, they will still be returned correctly, but stored internally as complex numbers -- so use the real( command on them if you want to pass them to commands that don't accept complex arguments.
Advanced
The ordinary formula above can give poor results if B is much larger than A and/or C. In that case, an alternate routine can be used:
√(B²+4ACi² If 0>real(Ansconj(B -Ans -.5(B+Ans {Ans/A,C/Ans
Formulas
The ordinary quadratic formula, and its alternate form are used:
<math> \begin{align} \mathrm{For} \hspace{5pt} ax^2+bx+c = 0, \\ \\ x = \frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ \\ x = \frac{2c}{-b\pm\sqrt{b^2-4ac}} \end{align} </math>